①(a-1)[1-(a+1)÷(a-1/a)]②3/3x-1=2x/2x^2-5② 3/(3x-1)=2x/(2x^2-
3个回答

(a-1)[1-(a+1)÷(a-1/a)] =(a-1)[1-(a+1)÷(a^2-1)/a]=(a-1)[1-(a+1)*a/(a+1)(a-1)]=(a-1)[1-a/(a-1)]=(a-1)*(-1)/(a-1)=-1

3/3x-1=2x/2x^2-5两边同时乘以(3x-1),(2x^2-5)

得6x^2-15=6x^2-2x x=15/2