分解因式 xy²-2xy+2y-4= 9x²-y²-4y-4= 4xy²-4x&
1个回答

xy²-2xy+2y-4

=xy(y-2)+2(y-2)

=(xy+2)(y-2)

9x²-y²-4y-4

=9x^2-(y^2+4y+4)

=9x^2-(y+2)^2

=(3x+y+2)(3x-y-2)

4xy²-4x²y-y³

=-y(y^2-4xy+4x^2)

=-y(2x-y)^2

- a²-1+b²-2a

= b²-a²-1-2a

=b^2-(a^2+2a+1)

=b^2-(a+1)^2

=(b+a+1)(b-a-1)

(99又¼)×(100又¾)

=(100-3/4)(100+3/4)

=100^2-(3/4)^2

=10000-9/16

=9999+7/16

=9999又7/16

100²-99²+98²-97²+…+4²-3²+2²-1²

=(100-99)(100+99)+(98-97)(98+97)+.+(4-3)(4+3)+(2-1)(2+1)

=100+99+98+97+...+4+3+2+1

=(1+100)*100/2

=5050

(1-2的平方分之一)(1-3的平方分之一)(1-4的平方分之一)…(1-10的平方分之一)=

=(1-1/2)(1+1/2)(1-1/3)1+1/3)(1-1/4)(1+1/4).(1-1/10)(1+1/10)

=1/2*3/2*2/3*4/3*3/4*5/4*.*9/10*11/10

=1/2*11/10

=11/20