1、解分式方程:X减2分之X 减1等于4减X²分之2
1个回答

1、解分式方程:X减2分之X 减1等于4减X²分之2

x/(x-2) -1=2/(4-x²)

x/(x-2) -1=-2/(x²-4)

x(x+2) -(x²-4)=-2

x²+2x -x²+4=-2

2x=-6

x=-3

经检验x=-3是方程的解

2

X²减1分之X²减2X÷(X减1减X加1分之2X减1)其中X等于2

=(x²-2x)/(x²-1) ÷(x-1 - (2x-1)/(x+1))

=x(x-2)/(x²-1) ÷ ((x-1)(x+1)-(2x-1))/(x+1)

=x(x-2)/(x²-1) ÷ (x^2-1-2x+1)/(x+1)

=x(x-2)/(x²-1) *(x+1)/ x(x-2)

=1/(x-1)

=1/(2-1)

=1