(x^3-3x^2+4x-4)=(x^3-2x^2-x^2+4x-4)=(x-2)(x^-x+2)
故(x^3-3x^2+4x-4)/(x-2)==x^-x+2
(3x^3+4x+3)/(x+2)=[(x+2)(3x^2-6x)+(16x+3]/(x+2)=3x^2-6x+(16x+3)/(x+2)
x^3-2x^2-5x+6=x^3-x^2-x^2-5x+6=x^2(x-1)-(x-1)(x+6)=(x-1)(x^-x-6)=(x-1)(x+2)(x-3)
x^3+x^2-5x+3=x^3-x+x^2-4x+3=x(x+1)(x-1)+(x-1)(x-3)=(x-1)(x^2+2x-3)=(x-1)^2(x+3)