给我出初二20道几何题10道化简求值题10道列方程的应用题应用题要有图带答案
3个回答

化简(1-1/x-1)/(x/x^-1)在选择一个适当的x求值

解(1-1/(x-1))/(x/(x^-1))

=((x-2)/(x-1))/(x/(x+1)(x-1))

=(x-2)/(x-1)*(x+1)(x-1)/x

=(x-2)(x+1)/x

当x=2时,原式=0

x适当的值一定不能是1,-1,0

2.、1/2(x+y+z)方+1/2(x-y-z)(x-y+z)-z(x+y),其中x-y=6,xy=21.要详细步骤

化简得:

1/2(x+y+z)方+1/2(x-y-z)(x-y+z)-z(x+y)=

1/2[(x+y)方+2z(x+y)+z方]+1/2[(x-y)方-z方]-z(x+y)=

1/2(x+y)方+1/2(x-y)方=x方+y方

由x-y=6,xy=21得,x方+y方=(x-y)方+2xy=78

3.9x+6x^2 -3(x-2/3x^2).其中x=-2

9x+6x² -3(x-2/3x²)

=9x+6x²-3x+2x²

=8x²+6x

=8×(-2)²+6×(-2)

=32-12

=20

4.9x+6x^2 -3(x-2/3x^2).其中x=-2

9x+6x² -3(x-2/3x²)

=9x+6x²-3x+2x²

=8x²+6x

=8×(-2)²+6×(-2)

=32-12

=20

5.1/4(-4x^2+2x-8)-(1/2x-1),其中x=1/2

1/4(-4x²+2x-8)-(1/2x-1)

=-x²+1/2x-2-1/2x+1

=-x²-1

=-(1/2)²-1

=-1/4-1

=-5/4

6.3x'y-[2x'y-(2xyz-x'z)-4x'z]-xyz,其中x=-2,y=-3,z=1,

:3x'y-[2x'y-(2xyz-x'z)-4x'z]-xyz

=3x'y-2x'y+2xyz-x'z+4x'z-xyz

=x'y-xyz+3x'z

=4*(-3)-2*3*1+3*4*1

=-12-6+12

=-6

7.(5a^2-3b^2)+(a^2+b^2)-(5a^2+3b^2),其中a=-1,b=1

=5a^2-3b^2+a^2+b^2-5a^2-3b^2

=a^2-5b^2

=(-1)^2-5*1^2

=1-5

=-4

8.2(a^2b+ab^2)-2(a^2 b-1)-2ab^2 -2其中a=-2,b=2

=2a^2b+2ab^2-2a^2b+2-2ab^2-2

=0

9.、(X-2分之1Y-1)(X-2分之1Y+1)-(X-2分之1Y-1)的平方

其中X=1.7,Y=3.9(先化简再求值)

[(X-2分之1Y)-1][(X+2分之1Y)+1]-(X-2分之1Y-1)平方

=(X+2分之1Y)平方-1-(X-2分之1Y)平方+2(X-2分之1Y)-1

=(X+2分之1Y)平方-(X-2分之1Y)平方+2(X-2分之1Y)-2

=2XY+2X-Y-2

=3.9*2.4+1.4

=10.76

10.先化简再求值,1/2a-(2a-2/3b^2)+(-3/2a+2b^2)其中a=-2,b=2/3

原式=-3a+8/3b^2

当a=-2,b=2/3时,

原式=6+8/3×(4/9)=194/27

这些怎么样,