化简:1,sin(pai/4-x)sin(pai/4+x) 2,cosA+cos(120度-A)+cos(120度+A)
6个回答

1,sin(pai/4-x)sin(pai/4+x)=cos(pai/4+x)sin(pai/4+x)

=sin(pai/2+2x)/2

=cos(2x)/2

2,cosA+cos(120度-A)+cos(120度+A)=cosA+2cos(120度)cosA

=cosA-cosA

=0

3,1+cos2a分之sin2a*1+cosa分之cosa=(sin2a*cosa)/(1+cos2a)*(1+cosa)

=2sina(cosa)^2/(cosa)^2*(cos[a/2])^2

=2sina/[cos(a/2)]^2

=4sin(a/2)cos(a/2)/[cos(a/2)]^2

=4sin(a/2)/cos(a/2)

=4tan(a/2)