设硝酸铵为x克,硫酸铵为1.06-x克.
2NH4NO3 + Ca(OH)2 ==== 2NH3(g) + Ca(NO3)2 + 2H2O
x g
x/80 mol x/80 mol
(NH4)2SO4 + Ca(OH)2 ==== 2NH3(g) + CaSO4 + 2H2O
1-x g
(1-x)/132 mol 2(1-x)/132 mol
336mL (0.336L) NH3物质的量:0.336/22.4 = 0.015 mol
x/80 + 2(1-x)/132 = 0.015
解得 x = 0.40 g
混合物中硝酸铵的质量分数为:0.4/1.06 = 0.377 = 37.7%