log2(√2-1)-log2((√2+1)=log2(x^2)
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要使log2(√2-1)-log2((√2+1)=log2(x^2) 有意义,X^2>0,即X>0,

log2(√2-1)-log2((√2+1)=log2(x^2)

log2[(√2-1)/(√2+1)]=log2(x^2)

(√2-1)/(√2+1)=x^2,

x^2=(√2-1)^2,(x>0)

x=(√2-1),

x+(1/x))的值=(√2-1)+1/(√2-1)=2√2.