1、将10g表面已被氧化成Na2O的钠块投入90.3g水中,充分反应后,得12g/cm3的溶液,同时放出3.36L气体(
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H2 (0.15mol (3.36/22.4) 0.3g ), Na 0.3mol 6.9g, Na2O 3.1g (3.1/62)0.05mol .0.35*12*1000/100 =42mol/L

2.6.72/22.4=0.3moL 即C的含量为0.3MOL 而NA的含量为0.4MOL可以得到

Na2CO3的含量为0.1mol 106*0.1/(106*0.1+84*0.3)=0.29608939