o(∩_∩)o ))一,化简(1)sin50°(1+√3tan10°)(2)y=(sinx+cosx)²+2cos²x(
1个回答

(1)=sin50°(1+√3tan10°)

=2sin50°(cos60°cos10°+sin60°sin10°)/cos10°

=2sin50°cos50°/cos10°

=sin100°/cos10°

=sin80°/cos10°

=cos10°/cos10°

=1

(2)

=1+2cosx*sinx+2cos²x-1+1

=sin2x+cos2x+2

=√2sin(2x+4/π)+2

(3)

=(cos²x-sin²x)*(cos²x+sin²x)-2sinx*cosx

=cos²x-sin²x-2sinxcosx

=cos2x-sin2x

=√2*sin(4/π-2x)

(4)

=2sinx*sinx+sin2x

=1-cos2x+sin2x

=√2sin(2x-4/π)+1

(5)

=sin(x+π/6)+sin(x-π/6)+cosx+a

=sinxcosπ/6+sinπ/6cosx+sinxcosπ/6-sinπ/6cosx+cosx+a

=√3倍sinx+cosx+a

=2sin(x+π/6)+a

2.

AC=H1/cos1AB=H2/sin2

角1=角2,

因为角4=90度,角1与角3互余,角2与角3互余,所以角1=角2

S=(AC*AB)/2=H1*H2/sin2 角1,

问面积最小,即令sin2 角1的值最大=1,

所以最小面积为H1*H2

对着图看