sin(α+π/4)+sin(α-π/4)
=sinαcosπ/4 + cosαsinπ/4 + sinαcosπ/4 - cosαsinπ/4
=2sinαcosπ/4
=√2 sinα
=√2/3
所以,sinα=1/3
sin(α-π/4)/1-cos2α-sin2α
=[sinαcosπ/4 - cosαsinπ/4]/[2sin²α-2sinαcosα]
=[√2/2sinα - √2/2cosα]/[2sin²α-2sinαcosα]
=[√2/2(sinα -cosα)]/[2sinα(sinα -cosα)]
=(√2/2)/(2sinα)
=3√2/4