2log3 2-log32/9+log3 8-5^log5 3
2个回答

应用公式:

①log3(M/N)=log3(M)-log3(N)

②log3(Mⁿ)=nlog3(M)

③M^logM(N)=N

2log3(2)-log3(2/9)+log3(8)-5^log5(3)

=2log3(2)-[log3(2)-log3(9)]+3log3(2)-3

=2log3(2)-log3(2)+2log3(3)+3log3(2)-3

=4log3(2)+2-3

=4log3(2)-1