1/1*3+1/3*5+1/5*7+.+1/(2n-1)(2n+1)=n/(2n+1)
2个回答

1/1*3=0.5*(1-1/3)=1/(1*2+1)

1/1*3+1/3*5=0.5*(1-1/3+1/3-1/5)=2/(2*2+1)

...

1/1*3+1/3*5+1/5*7+.+1/(2n-1)(2n+1)

=1/2{1-1/3+1/3-1/5+.+1/(2n-1)-1/(2n+1)}

=1/2{1-1/(2n+1)}

=n/(2n+1)

1/1*3+1/3*5+1/5*7+.+1/(2n-1)(2n+1)+1/(2n+1)(2n+3)

=1/2{1-1/3+1/3-1/5+.+1/(2n-1)-1/(2n+1)+1/(2n+1)-1/(2n+3)}

=1/2{1-1/(2n+3)}

=(n+1)/[2(n+1) +1]

所以

1/1*3+1/3*5+1/5*7+.+1/(2n-1)(2n+1)=0.5*(1-1/3+1/3-1/5.-1/(2n+1))

=n/(2n+1)