以下求各图形阴影部分的周长和面积
2个回答

C=(3×2)π/4+3+3+(1+1)π

=3.5π+6

=16.99

S=3²-3²π/4+1²π/4

=9-2π

=2.72

C=(2×2)π/4+√(2²+1²)+(1×2)π/4+1

=1.5π+1+√5

=5.71+√5

S=2²π/4-2×1÷2+1²π/4

=1.25π-1

=2.925

C=4²π/4+√[(8+4)²+4²]+8

=4π+4√10+8

=4.56+4√10

S=(8+4)×4÷2-(4×4-4²π/4)

=8+4π

=20.56

C=4π/2+4

=2π+4

=10.28

S=2×2

=4