因式分解练习题6x^2-7xy-3y^2-xz+7yz-2z^22x^4-x^3-6x^2-x+2(x+1)^4+(x+
2个回答
1.6X^2-7xy-3y^2-xz+7yz-2z^2=(3x+y-2z)(2x-3y+z)
2.（2x-1）(x^3-3x-2)=(2x-1)[x(x-2)(x+2)+(x-2)]
=（2x-1）(x-2)(x^2+2x+1)=（2x-1）(x-2)(x+1)^2
3.（x+1）^4+(x+3)^4-272
=(x+3)^4-4^4+(x+1)^4-2^4
（平方差）
=[(x+3)^2-4^2][(x+3)^2+4^2]+[(x+1)^2-2^2][(x+1)^2+2^2]
（平方差）
=(x-1)(x+7)[(x+3)^2+4^2]+(x-1)(x+3)[(x+1)^2+2^2]
（提取公因式,再整理）
=2(x-1)（x^2+4x+19)(5+x)
4.xy(xy+1)+(xy+3)-2(x+y+0.85)-(x+y-1)^2=(xy)^2-x^2-y^2+0.3
5.x^3+8y^3-z^3+6xyz=(x+2y-z)(x^2+4y^2+z^2-2xy+xz-2yz)
6.原式=(x+2y+2)(x+3y+6)．
7.x^2+2xy-8y^2+2x+14y-3
=(x^2+2xy-8y^2)-(x-2y)+3(x+4y)-3
=(x-2y)(x+4y)-(x-2y)+3(x+4y)-3
=(x-2y+3)(x+4y-1).
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