根据打出的纸带,如图,选取纸带上打出的五个点,A、B、C、D、E,测出A点距离点O的距离为x,
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(1),x1+x2=s2=vt2+at²/2=v·4T+a(4T)²/2 ···①

x1=s1=vt1+at²/2=v·2T+a(2T)²/2 ···②

①-2x②,得,s2-s1=(x2+x1)-2·x1=a·4T²

∴a=(x2-x1)/(4T²).

(2),F阻力=m(g-a)=m【g-(x2-x1)/(4T²)】.

解毕.