求解(x-1/2)(x的平方+1/4)(x+1/2)
1个回答

(x-1/2)(x^2+1/4)(x+1/2)

=(x-1/2)(x+1/2)(x^2+1/4)

=(x^2-1/4)(x^2+1/4)

=x^4-1/16

(x+y-z)(x+y+z)

=[(x+y)-z][(x+y)+z]

=(x+y)^2-z^2

=x^2+2xy+y^2-z^2

(a-b+c)(a+b-c)

=[a-(b-c)][a+(b-c)]

=a^2-(b-c)^2

=a^2-b^2+2bc-c^2

[2a^2-(a+b)(a-b)][(c-a)(c+a+(b-c)c+b)]

=(2a^2-a^2+b^2)[(c-a)(c+a+bc-c^2+b)]

=(a^2+b^2)[(c-a)(c+a+bc-c^2+b)]……你看下后面的括号对么,题目应该不会出这样的

(a+b+c)^2-(a-b+c)^2

=(a+b+c+a-b+c)(a+b+c-a+b-c)

=(2a+2c)2b

=4ab+4bc

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