(2^2+1)(2^4+1)( 2^8+1)( 2^16+1)( 2^32+1)( 2^64+1)+1这道题可以做吗
1个回答
(2^2+1)(2^4+1)( 2^8+1)( 2^16+1)( 2^32+1)( 2^64+1)+1
=(2^2+1)*[（2^2-1)/(2^2-1)]*(2^4+1)( 2^8+1)( 2^16+1)( 2^32+1)( 2^64+1)+1
=(2^4-1)(2^4+1)( 2^8+1)( 2^16+1)( 2^32+1)( 2^64+1)/(2^2-1)+1
=(2^8-1))( 2^8+1)( 2^16+1)( 2^32+1)( 2^64+1)/(2^2-1)+1
=(2^16-1))( 2^16+1)( 2^32+1)( 2^64+1)/(2^2-1)+1
=(2^32-1))(2^32+1)( 2^64+1)/(2^2-1)+1
=(2^64-1)( 2^64+1)/(2^2-1)+1
=(2^128-1)/3+1
=(2^128-1+3)/3
=(2^128+2)/3
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