两道二元二次方程(1){y²=2x ① x²+y²=8 ②} (2){3x²-2
1个回答

(1)

y²=2x ①

x²+y²=8 ②

①代入②得

x²+2x-8=0

(x+4)(x-2)=0

x=-4或x=2

∵y²=2x>=0

∴x=2

y=±2

综上x=2,y=2或x=2,y=-2

(2)

3x²-2xy-y²=0

(3x+y)(x-y)=0①

(x-y)²-3(x-y)-18=0

(x-y-6)(x-y+3)=0②

由①得

y=-3x或y=x

而y=x时,x-y=0,则②不成立,舍去

∴y=-3x

代入②得

(4x-6)(4x+3)=0

x=3/2或x=-3/4

y=-9/2或y=9/4

综上x=3/2,y=-9/2或x=-3/4,y=9/4