49(a-b)^2-16(b-a)^2
3个回答

49(a-b)^2-16(b-a)^2

=49(a-b)^2-16(a-b)^2

=(a-b)^2(49-16)

=33(a-b)^2

x^2+y^2-2x+8y+17=0

x^2-2x+1+y^2+8y+18=0

(x-1)^2+(y+4)^2=0

因为(x-1)^2>=0 (y+4)^2>=0

所以(x-1)^2=(y+4)^2=0

x-1=y+4=0

x=1,y=-4

2x+3y

=2*1+3*(-4)

=2-12

=-10