13-14----和1求解,
1个回答

13.原式=cos²28°+cos²(90°-28°)+ tan33°·tan(90°-33°)

=cos²28°+sin²28°+ tan33°·cot33°

=1+1

=2

14.原式

=tan(-180°+30°)cos(-180°-30°)cos(360°+60°)/[cos(-720°+120°)sin(-360°+30°)]

=tan30°cos30°cos60°/[cos120°sin30°]

=sin30°cos60°/[cos60°sin30°]

=1

1.tan(11π/3)=tan(4π - π/3 )

=tan( π/3 )

=√3