a(x-y)^2n-b(y-x)^2n+1(分解因式)
1个回答

a(x-y)^2n-b(y-x)^2n+1

=a(y-x)^2n-b(y-x)^2n+1

=(y-x)^2n*(a-by+bx)

(a-b)²(a+b)³-(b-a)²(b+a)²

=(a-b)²(a+b)²(a+b-1)

2(a-b)²-a+b

=(a-b)(2a-2b-1)

-x²(m-n)^5-xy(n-m)³

=-x²(m-n)^5+xy(m-n)³

=-x(m-n)³[x(m-n)²-y]

=-x(m-n)³(xm²-2mnx+xn²-y)

35ab(x-y)²-25a²b²(y-x)²+10ab³(y-x)³

=5ab(x-y)²(7-5ab-2bx+2by)