当另一动点Q以每秒钟1个单位长度的速度从原点O向右运动时,同时点A以每秒钟4个单位长度向右运动,点B以每秒钟2个单位长度
1个回答

xQ = 1*t = t

xA = -3+4*t = -3+4t

xB = 1+2*t = 1+2t

QA=2QB

|xQ-xA| = 2|xQ-xB|

|t-(-3+4t)| = 2|t-(1+2t)|

|3t-3| = |2t+2|

3t-3 = 2t+2,或3t-3=-2t-2

t=5,或t=1/5

1/5秒后,或5秒后,QA=2QB