【答】:
电解AgNO3的反应方程式是
4AgNO3 + 2H2O =电解= 4Ag + O2 + 4HNO3
所以,生成的Ag与HNO3等mol
n(Ag)=n(H+)=(10^-3 - 10^-6)*0.5=0.0005mol
m(Ag)=0.0005*108=0.054g
2NaCl +2H2O→2NaOH + Cl2 +H2
n(H2)= 5.6 / 22.4 = 0.25mol
n(NaOH) = 0.25 * 2 = 0.5mol
n1(OH-) = [(10^-8)/(10^-14)] * 0.5 = (10^-6) * 0.5mol
n2(OH-) = 0.5mol
n(OH-) = 0.5mol(jinshizhi)
c(OH-) = 0.5mol/0.5L = 1mol/L
pH = 14