1.方程组:(a+3)(b-2)=(a-4)(b+7)解方程组
ab+3b-2a-6=ab-4b+7a-28
9a-7b-22=0
a=3 b=1
2.在(ax+3y)与(x-y)的积中,不含有xy项,则a为?
(ax+3y)(x-y)
=ax^2+3xy-axy-3y^2
3-a=0
a=3
3.已知a²+a-1=0,求(a²+3)(a+2)-3-3a的值
(a^2+3)(a+2)-3-3a
=a^3+2a^2+3a+6-3a-3
=a^3+2a^2+3
=a(a^2+a-1)+a^2+a+3
=1+3=4