#include
#include
int main(void) //求方程ax^2+bx+c=0的解
{
float a,b,c,disc,x1,x2,realpart,imagpart;
scanf("%f,%f,%f",&a,&b,&c);
printf("The equation");
if(fabs(a)0,方程有两个不相等的实数根
{
x1=(-b+sqrt(disc))/(2*a); //sqrt()为开平方根函数
x2=(-b-sqrt(disc))/(2*a);
printf("has distinct real roots:%8.4f and %8.4fn",x1,x2);
}
else //disc