//对d的正负要做判!
#include
#include
void main ()
{
double a,b,c,d,x1,x2;
scanf("%lf%lf%lf",&a,&b,&c);
d=b*b-4*a*c;
if (d > 0)
{
x1=(-b-sqrt(d))/(2*a);
x2=(-b+sqrt(d))/(2*a);
printf("%.2lf %.2lfn",x1,x2);
}
else if (d < 0)
printf("无解n");
else
printf("x1 = x2 = %.2lfn", -b / (2 * a));
}