2L密闭容器中反应,半分钟内C的物质的量增加了0.6mol,则:v(C)=
0.6mol
2L
30s =0.01mol/(L•s),
A、速率之比等于化学计量数之比,故v(A)=
1
2 v(C)=
1
2 ×0.01mol/(L•s)=0.005mol/(L•s),故A正确;
B、v(C)=
0.6mol
2L
30s =0.01mol/(L•s),故B错误;
C、速率之比等于化学计量数之比,故v(B)=
3
2 v(C)=
3
2 ×0.01mol/(L•s)=0.015mol/(L•s),故C错误;
D、速率之比等于化学计量数之比,故v(A)=
1
2 v(C)=
1
2 ×0.01mol/(L•s)=0.005mol/(L•s),故D错误;
故选A.