几道数学题(分解因式)1.x^2+2xy+4(x+1)+y^2+4y2.(1-a^2)(1-b^2)-4ab3.a^2(
1个回答

1.x^2+2xy+4(x+1)+y^2+4y

=(x^2+2xy+y^2)+4x+4y+4

=(x+y)^2+4(x+y)+4

=(x+y+2)^2

2.(1-a^2)(1-b^2)-4ab

=1-a^2-b^2+a^2b^2-4ab

=(a^2b^2-2ab+1)-(a^2+2ab+b^2)

=(ab-1)^2-(a+b)^2

=(ab+a+b-1)(ab-a-b-1)

3.a^2(b-c)+b^2(c-a)+c^2(a-b)

=a^2b-a^2c+b^2c-b^2a+c^2a-c^2b

=ab(a-b)+bc(b-c)+ac(c-a)

=b(a^2-ab+cb-c^2)+ac(c-a)

=b[(a+c)(a-c)-b(a-c)]+ac(c-a)

=b(a-c)(a+b-c)-ac(a-c)

=(a-c)(ab+b^2-bc-ac)

=(a-c)(a-b)(b-c)

4.x^3+x^2+x-3

=(x^3-1)+(x^2-1)+(x-1)

=(x-1)(x^2+x+1)+(x-1)(x+1)+(x-1)

=(x-1)(x^2+x+1+x+1+1)

=(x-1)(x^2+2x+3)

5.a^3-4a^2-4a-5

=a^3-5a^2+a^2-4a-5

=a^2(a-5)+(a+1)(a-5)

=(a-5)(a^2+a+1)

6.a^3-6a^2+11a-6

=(a^3-1)-(6a^2-11a+5)

=(a-1)(a^2+a+1)-(6a-5)(a-1)

=(a-1)(a^2+a+1-6a+5)

=(a-1)(a^2-5a+6)

=(a-1)(a-2)(a-3)

7.(x+1)(x+2)(x+3)(x+4)-24

=[(x+1)(x+4)][(x+2)(x+3)]-24

=[(x^2+5x)+4][(x^2+5x)+6]-24

=(x^2+5x)^2+10(x^2+5x)+24-24

=(x^2+5x)(x^2+5x+10)

=x(x+5)(x^2+5x+10)