答案为19/41.依题意得:
设:{an}公差为d1.{bn}公差为d2:
sn=a1n+d1n(n-1)/2,tn=b1n+d2n(n-1)/2;
sn/tn=[a1n+d1n(n-1)/2]/[b1n+d2n(n-1)/2]
=[2a1+d1(n-1)]/[2b1+d2(n-1)]=(2n-3)/(4n-3);
a9/(b5+b7) + a3/(b8+b4)
=[a1+8d1]/[2b1+10d2]+[a1+2d1]/[2b1+10d2]
=[2a1+10d1]/[2b1+10d2];
当n=11时,a9/(b5+b7) + a3/(b8+b4)
=(2×11-3)/(4×11-3)=19/41;