跪求30道有理数加减乘除计算带过程急!
1个回答

3+2^2×(-1/5)

原式=3+4×(-1/5)

=3-4/5

=11/5

18-6÷(-2)×(-1/3)

原式=18-(-3)×(-1/3)

=18-1

=17

(-3)^2×[-2/3+(-5/9)]

原式=9×(-11/9)

=-11

8+(-3)^2×(-2)

原式=8+9×(-2)

=8-18

=-10

100÷(-2)^2-(-2)÷(-2/3)

原式=100÷4-3

=25-3

=22

36×(1/2-1/3)^2

原式=36×(1/6)^2

=36×(1/36)

=1

12.7÷(-8/19)×0

原式=0

4×(-3)^2+6

原式=4×9+6

=36+6

=42

(-3/4)×(-8+2/3-1/3)

原式=(-3/4)×(-8+1/3)

=(-3/4)×(-23/3)

=23/4

(-2)^3-13÷(-1/2)

原式=(-8)-(-26)

=18

0-2^3÷(-4)^3-1/8

原式=0-8÷(-64)-1/8

=0+1/8-1/8

=0

(-2)^3×0.5-(-1.6)^2÷(-2)^2

原式=(-8)×(1/2)-(-8/5)^2÷4

=(-4)-(64/25)÷4

=(-4)-16/25

=-116/25

(-3/2)×[(-2/3)^2-2]

原式=(-3/2)×(4/9-2)

=(-3/2)×(-14/9)

=7/3

[(-3)^2-(-5)^2]÷(-2)

原式=(9-25)÷(-2)

=(-16)÷(-2)

=8

16÷(-2)^3-(-1/8)×(-4)

原式=16÷(-8)-1/2

=-2-1/2

=-5/2

2×(-5)+2^2-3÷1/2

原式=-10+4-3×2

=-10+4-6

=-12.

17-2^3÷(-2)×3

原式=17-8÷(-2)×3,

=17-(-4)×3,

=17+12,

=29.

(-1/2)^0+(-2)^3+(1/3)^-1+|-2|

原式=1-8+3+2

=-2.

(-2)^3÷(-1-3)-(1/2)^(-1)+(3.14-π)^0

原式=-8÷(-4)-2+1

=2-2+1

=1.

-3^4+(-0.25)^100×4^100+(1/2-1/3)×(1/6)^-2÷|-2|

原式=-81+1+1/6 ×36×1/2

=-81+1+3

=-77

2^2+4×(-1/2)

原式=4-2=2

(-2)^3+|-7|-3^0

原式=-8+7-1

=-2

-1^100-(1-0.5)×1/3×[3-(-3)^2]

原式=-1-1/2 ×1/3 ×(-6)

=-1+1

=0

-1^4-1/6×[2-(-3)^2]

原式=-1-1/6 ×(2-9)

=-1-1/6 ×(-7)

=-1+7/6

=1/6

-12+8÷(-2)^3-(-5)×(-3)

原式=-12+8÷(-8)-15

=-12+(-1)-15

=-28

(-24)×(1/8-1/3+1/4)+(-2)^3

原式=-3+8-6-8=-9

-1^4-(1-0.5)×1/3×[1-(-3)^2]

原式=-1-1/2 ×1/3 ×(1-9)

=-1+1/2 ×1/3 ×8

=-1+4/3

=1/3

(3/4-7/8+5/12)×(-24);

原式=-3/4 ×24+7/8 ×24-5/12 ×24

=-18+21-10

=-7

-1^4-1/6×[2+(-4)^2]

原式=-1-1/6 ×(2+16)=-1-3=-4