用C语言编写一个简易计算器可实现加减乘除,连加连减,连乖连除.
1个回答

#include

#include"stdlib.h"

#define N 10

void fun()

{

int a,b,t;

char c;

scanf("%d",&a);

scanf(" %c",&c);

scanf("%d",&b);

if(c=='+'||c=='-'||c=='*'||c=='/'||c=='%')

{

if(c=='+') t=a+b;

if(c=='-') t=a-b;

if(c=='*') t=a*b;

if(c=='%') t=a%b;

if(c=='/')

{

if(b==0)

{

printf("0不能做除数n");

}

else

t=a/b;

}

printf("%d%c%d=%dn",a,c,b,t);

}

else printf("运算符号错误!n");

}

void main()

{

int i;

char quit;

for(i=0;i

{

fun();

printf("是否继续(y/n)?n");

scanf(" %c", quit);

if(quit=='Y'||quit=='y') {

system("cls");//清屏函数 头文件为stdlib.h

continue;

}

if(quit=='N'||quit=='n') break;

}

}#include

int jia(int a,int b)

{

int s;

s=a+b;

return s;

}

int jian(int a,int b)

{

int s;

s=a-b;

return s;

}

int cheng(int a,int b)

{

int s;

s=a*b;

return s;

}

int chu(int a,int b)

{

int s;

s=a/b;

return s;

}

void main()

{

int a,b,x,y,i;

char c;

printf("请输入运算式:n");

scanf("%d%c%d",&a,&c,&b);

x=a;

y=b;

for(i=0;;i++)

{

if(c=='+')x=jia(x,y);

else if(c=='-')x=jian(x,y);

else if(c=='*')x=cheng(x,y);

else if(c=='/')x=chu(x,y);

c=getchar();

if(c=='=')

{

printf("%dn",x);

break;

}

scanf("%d",&y);

}

}