已知a,b,c是都不相等的实数,且a(y-z)+b(z-x)+c(x-y)=0,求证:(x-y)/(a-b)=(y-z)
2个回答

证明:

令a(y+z)=b(x+y)=c(x+z)=k

则有:

y+z=k/a①

x+y=k/b②

x+z=k/c③

由①+②+③得:

x+y+z=1/2k(1/a+1/b+1/c)④

由④-①,④-②,④-③分别可得:

x=1/2k(1/b+1/c-1/a)

y=1/2k(1/a+1/b-1/c)

z=1/2k(1/a+1/c-1/b)

∴y-z/a(b-c)=1/2k(1/a+1/b-1/c-1/a+1/b-1/c)/a(b-c)

=(c-b)k/abc(b-c)

=-k/abc

同理,z-x/b(c-a)=-k/abc

x-y/c(a-b)=-k/abc

∴y-z/a(b-c)=z-x/b(c-a)=x-y/c(a-b)