sin7π/18cos2π/9-sinπ/9sin2π/9的值
1个回答

sinπ/9=sin2π/18=cos(π/2-2π/18)=cos(9π/18-2π/18)=cos7π/18

原式=sin7π/18cos2π/9-cos7π/18sin2π/9 (利用两角差的公式可知)

=sin(7π/18-2π/9)

=sin(7π/18-4π/18)

=sin3π/18

=sinπ/6

=1/2

教你记公式的方法:

正余余正符号同,余余正正符号异